<!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <script src="http://www.jb51.net/ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script> <title>jquery 获取鼠标指针的坐标</title> <script> //普通js函数 function test(event) { event = event || window.event; var x = event.offsetX || event.layerX; var y = event.offsetY || event.layerY; alert("x="+x+"; y="+y); } //jquery函数 $(function(){ $("#t").mouseover( function(event){ event = event || window.event; var x = event.offsetX || event.originalEvent.layerX; var y = event.offsetY || event.originalEvent.layerY; alert("x:"+x+"; y:"+y); } ); }); </script> </head> <body> <div id="t">测试鼠标位置（jquery函数处理）</div> <div id="s" onmouseover="test(event)">测试鼠标位置（普通js函数处理）</div> </body> </html>
【Js和JQuery获取鼠标指针坐标的实现代码分享】相关文章：