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oracle sql select语句的使用方法
摘要:select格式:SELECT[ALL|DISTINCT]select*fromhkb_test22union3select*fromhkb...

select格式:

SELECT [ ALL | DISTINCT ] <字段表达式1[,<字段表达式2[,…]

FROM <表名1>,<表名2>[,…]

[WHERE <筛选择条件表达式>]

[GROUP BY <分组表达式> [HAVING<分组条件表达式>]]

[ORDER BY <字段>[ASC | DESC]]

语句说明:

[]方括号为可选项

[GROUP BY <分组表达式> [HAVING<分组条件表达式>]]

指将结果按<分组表达式>的值进行分组,该值相等的记录为一组,带【HAVING】

短语则只有满足指定条件的组才会输出。

[ORDER BY <字段>[ASC | DESC]]

显示结果要按<字段>值升序或降序进行排序

练习:

1:表hkb_test_sore取出成绩sore前5名的记录,

2:取第5名的记录

1,答案select a.sore_id, a.sore

from (select * from hkb_test_sore order by sore desc) a

where rownum <=5

2,答案select a.sore_id, a.sore

from (select * from hkb_test_sore order by sore desc) a

where rownum <=5

minus

select a.sore_id, a.sore

from (select * from hkb_test_sore order by sore desc) a

where rownum <=4;

3:查询两个分数一样的记录

select *

from hkb_test_sore a

where a.sore = (select sore

from hkb_test_sore a

group by a.sore

having count(a.sore) = 2);

union,union all,intersect,minus的区别:

SQL> select * from hkb_test2;

X Y

---- -----

a 1

b 2

c 3

g 4

SQL> select * from hkb_test3;

X Y

---- -----

a 1

b 2

e 3

f 4

SQL> select * from hkb_test2;

X Y

---- -----

a 1

b 2

c 3

g 4

SQL> select * from hkb_test3;

X Y

---- -----

a 1

b 2

e 3

f 4

SQL> select * from hkb_test2

2 union

3 select * from hkb_test3;

X Y

---- -----

a 1

b 2

c 3

e 3

f 4

g 4

6 rows selected

SQL> select * from hkb_test2

2 union all

3 select * from hkb_test3;

X Y

---- -----

a 1

b 2

c 3

g 4

a 1

b 2

e 3

f 4

8 rows selected

SQL> select * from hkb_test2

2 intersect

3 select * from hkb_test3;

X Y

---- -----

a 1

b 2

SQL> select * from hkb_test2

2 minus

3 select * from hkb_test3;

X Y

---- -----

c 3

g 4

综合上面实例看个完整的实例

SQL>

SQL>

SQL> -- create demo table

SQL> create table Employee(

2 ID VARCHAR2(4 BYTE) NOT NULL primary key,

3 First_Name VARCHAR2(10 BYTE),

4 Last_Name VARCHAR2(10 BYTE),

5 Start_Date DATE,

6 End_Date DATE,

7 Salary Number(8,2),

8 City VARCHAR2(10 BYTE),

9 Description VARCHAR2(15 BYTE)

10 )

11 /

Table created.

SQL>

SQL> -- prepare data

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values ('01','Jason', 'Martin', to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto', 'Programmer')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('02','Alison', 'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('03','James', 'Smith', to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('04','Celia', 'Rice', to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('05','Robert', 'Black', to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('06','Linda', 'Green', to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York', 'Tester')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('07','David', 'Larry', to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York', 'Manager')

3 /

1 row created.

SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

2 values('08','James', 'Cat', to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')

3 /

1 row created.

SQL>

SQL>

SQL>

SQL> -- display data in the table

SQL> select * from Employee

2 /

ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION

---- -------------------- -------------------- --------- --------- ---------- ---------- ---------------

01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer

02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester

03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester

04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager

05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester

06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester

07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager

08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester

8 rows selected.

SQL>

SQL>

SQL> SELECT id, first_name, last_name FROM employee

2 /

ID FIRST_NAME LAST_NAME

---- -------------------- --------------------

01 Jason Martin

02 Alison Mathews

03 James Smith

04 Celia Rice

05 Robert Black

06 Linda Green

07 David Larry

08 James Cat

8 rows selected.

在ORACLE中实现SELECT TOP N的方法

1.在ORACLE中实现SELECT TOP N

由于ORACLE不支持SELECT TOP语句,所以在ORACLE中经常是用ORDER BY跟ROWNUM的组合来实现SELECT TOP N的查询。

简单地说,实现方法如下所示:

SELECT 列名1...列名n FROM

(SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N(抽出记录数)

ORDER BY ROWNUM ASC

下面举个例子简单说明一下。

顾客表customer(id,name)有如下数据:

ID NAME

01 first

02 Second

03 third

04 forth

05 fifth

06 sixth

07 seventh

08 eighth

09 ninth

10 tenth

11 last

则按NAME的字母顺抽出前三个顾客的SQL语句如下所示:

SELECT * FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= 3

ORDER BY ROWNUM ASC

输出结果为:

ID NAME

08 eighth

05 fifth

01 first

2.在TOP N纪录中抽出第M(M <= N)条记录

在得到了TOP N的数据之后,为了抽出这N条记录中的第M条记录,我们可以考虑从ROWNUM着手。我们知道,ROWNUM是记录表中数据编号的一个隐藏子段,所以可以在得到TOP N条记录的时候同时抽出记录的ROWNUM,然后再从这N条记录中抽取记录编号为M的记录,即使我们希望得到的结果。

从上面的分析可以很容易得到下面的SQL语句。

SELECT 列名1...列名n FROM

(

SELECT ROWNUM RECNO, 列名1...列名nFROM

(SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N(抽出记录数)

ORDER BY ROWNUM ASC

)

WHERE RECNO = M(M <= N)

同样以上表的数据为基础,那么得到以NAME的字母顺排序的第二个顾客的信息的SQL语句应该这样写:

SELECT ID, NAME FROM

(

SELECT ROWNUM RECNO, ID, NAME FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= 3

ORDER BY ROWNUM ASC )

WHERE RECNO = 2

结果则为:

ID NAME

05 fifth

3.抽出按某种方式排序的记录集中的第N条记录

在2的说明中,当M = N的时候,即为我们的标题讲的结果。实际上,2的做法在里面N>M的部分的数据是基本上不会用到的,我们仅仅是为了说明方便而采用。

如上所述,则SQL语句应为:

SELECT 列名1...列名n FROM

(

SELECT ROWNUM RECNO, 列名1...列名nFROM

(SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N(抽出记录数)

ORDER BY ROWNUM ASC

)

WHERE RECNO = N

那么,2中的例子的SQL语句则为:

SELECT ID, NAME FROM

(

SELECT ROWNUM RECNO, ID, NAME FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= 2

ORDER BY ROWNUM ASC

)

WHERE RECNO = 2

结果为:

ID NAME

05 fifth

4.抽出按某种方式排序的记录集中的第M条记录开始的X条记录

3里所讲得仅仅是抽取一条记录的情况,当我们需要抽取多条记录的时候,此时在2中的N的取值应该是在N >= (M + X - 1)这个范围内,当让最经济的取值就是取等好的时候了的时候了。当然最后的抽取条件也不是RECNO = N了,应该是RECNO BETWEEN M AND (M + X - 1)了,所以随之而来的SQL语句则为:

SELECT 列名1...列名n FROM

(

SELECT ROWNUM RECNO, 列名1...列名nFROM

(

SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

WHERE ROWNUM <= N (N >= (M + X - 1))

ORDER BY ROWNUM ASC

)

WHERE RECNO BETWEEN M AND (M + X - 1)

同样以上面的数据为例,则抽取NAME的字母顺的第2条记录开始的3条记录的SQL语句为:

SELECT ID, NAME FROM

(

SELECT ROWNUM RECNO, ID, NAME FROM

(SELECT * FROM CUSTOMER ORDER BY NAME)

WHERE ROWNUM <= (2 + 3 - 1)

ORDER BY ROWNUM ASC

)

WHERE RECNO BETWEEN 2 AND (2 + 3 - 1)

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