查找所有重复标题的记录：
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| 1 | SELECT * FROM t_info a WHERE ((SELECT COUNT(*) FROM t_info WHERE Title = a.Title) 1) ORDER BY Title DESC |
一、查找重复记录
1、查找全部重复记录
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| 1 | Select * From 表 Where 重复字段 In (Select 重复字段 From 表 Group By 重复字段 Having Count(*)1) |
2、过滤重复记录(只显示一条)
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| 1 | Select * From HZT Where ID In (Select Max(ID) From HZT Group By Title) |
注：此处显示ID最大一条记录
二、删除重复记录
1、删除全部重复记录(慎用)
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| 1 | Delete 表 Where 重复字段 In (Select 重复字段 From 表 Group By 重复字段 Having Count(*)1) |
2、保留一条(这个应该是大多数人所需要的 ^_^)
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| 1 | Delete HZT Where ID Not In (Select Max(ID) From HZT Group By Title) |
注：此处保留ID最大一条记录
三、举例
1、查找表中多余的重复记录，重复记录是根据单个字段(peopleId)来判断
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| 1 | select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) 1) |
2、删除表中多余的重复记录，重复记录是根据单个字段(peopleId)来判断，只留有rowid最小的记录
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| 1 2 | delete from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) 1) and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )1) |
3、查找表中多余的重复记录(多个字段)
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| 1 | select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) 1) |
4、删除表中多余的重复记录(多个字段)，只留有rowid最小的记录
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| 1 2 | delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)1) |
5、查找表中多余的重复记录(多个字段)，不包含rowid最小的记录
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| 1 2 | select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)1) |
四、补充
有两个以上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复，比较容易解决，使用
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| 1 | select distinct * from tableName |
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录(重复记录保留1条)，可以按以下方法删除
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| 1 2 3 4 | select distinct * into #Tmp from tableName drop table tableName select * into tableName from #Tmp drop table #Tmp |
发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。
2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下
假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集
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| 1 2 3 | select identity(int,1,1) as autoID, * into #Tmp from tableName select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID select * from #Tmp where autoID in(select autoID from #tmp2) |
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