手机
当前位置:查字典教程网 >编程开发 >php教程 >php 判断访客是否为搜索引擎蜘蛛的函数代码
php 判断访客是否为搜索引擎蜘蛛的函数代码
摘要:复制代码代码如下:/***判断是否为搜索引擎蜘蛛**@authorEddy*@returnbool*/functionisCrawler()...

复制代码 代码如下:

/**

* 判断是否为搜索引擎蜘蛛

*

* @author Eddy

* @return bool

*/

function isCrawler() {

$agent= strtolower($_SERVER['HTTP_USER_AGENT']);

if (!empty($agent)) {

$spiderSite= array(

"TencentTraveler",

"Baiduspider+",

"BaiduGame",

"Googlebot",

"msnbot",

"Sosospider+",

"Sogou web spider",

"ia_archiver",

"Yahoo! Slurp",

"YoudaoBot",

"Yahoo Slurp",

"MSNBot",

"Java (Often spam bot)",

"BaiDuSpider",

"Voila",

"Yandex bot",

"BSpider",

"twiceler",

"Sogou Spider",

"Speedy Spider",

"Google AdSense",

"Heritrix",

"Python-urllib",

"Alexa (IA Archiver)",

"Ask",

"Exabot",

"Custo",

"OutfoxBot/YodaoBot",

"yacy",

"SurveyBot",

"legs",

"lwp-trivial",

"Nutch",

"StackRambler",

"The web archive (IA Archiver)",

"Perl tool",

"MJ12bot",

"Netcraft",

"MSIECrawler",

"WGet tools",

"larbin",

"Fish search",

);

foreach($spiderSite as $val) {

$str = strtolower($val);

if (strpos($agent, $str) !== false) {

return true;

}

}

} else {

return false;

}

}

网上倒是能搜到一大把,不过都是千篇一律的复制来复制去的,也不够全面,我这里整理了一份比较全面的代码:

复制代码 代码如下:

function is_spider(){

$robot = 0;

$USER_AGENT = strtolower($_SERVER['HTTP_USER_AGENT']);

if(strpos($USER_AGENT,"bot")) $robot = 1;

if(strpos($USER_AGENT,"spider")) $robot = 1;

if(strpos($USER_AGENT,"slurp")) $robot = 1;

if(strpos($USER_AGENT,"mediapartners-google")) $robot = 1;

if(strpos($USER_AGENT,"fast-webcrawler")) $robot = 1;

if(strpos($USER_AGENT,"altavista")) $robot = 1;

if(strpos($USER_AGENT,"ia_archiver")) $robot = 1;

if($robot == 1){

//do something

}

return '';

}

【php 判断访客是否为搜索引擎蜘蛛的函数代码】相关文章:

php eval函数一句话木马代码

php实现比较两个字符串日期大小的方法

PHP 判断数组是否为空的5大方法

PHP验证信用卡卡号是否正确函数

php中数据的批量导入(csv文件)

复杂检索数据并分页显示的处理方法

php删除指定目录的方法

php支持中文字符串分割的函数

php页面缓存ob系列函数介绍

PHP SPL标准库中的常用函数介绍

精品推荐
分类导航