复制代码 代码如下:

rem DOS get current time

rem =======================

rem get yyyy/mm/dd

set mydate=%DATE:~0,10%

echo %mydate%

rem =======================

rem get yyyy

set yyyy=%DATE:~0,4%

echo %yyyy%

rem =======================

rem get mm

set mm=%DATE:~5,2%

echo %mm%

rem =======================

rem get dd

set dd=%DATE:~8,2%

echo %dd%

rem =======================

rem get yyyy-mm-dd

set curdate=%yyyy%-%mm%-%dd%

echo %curdate%

其实bat中获取时间就是利用截取日期字符串的方法

DOS下有字符处理的方法的，总结如下：

在这个日期格式下：”2013-07-22 星期一”， 这个%DATE:~0,10%得到的是2013-07-22

说明：DATE为系统变量，“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。

输出：

C:Documents and SettingsAdministrator>rem DOS get current time

C:Documents and SettingsAdministrator>rem =======================

C:Documents and SettingsAdministrator>rem get yyyy/mm/dd

C:Documents and SettingsAdministrator>set mydate=2013-07-22

C:Documents and SettingsAdministrator>echo 2013-07-22

2013-07-22

C:Documents and SettingsAdministrator>rem =======================

C:Documents and SettingsAdministrator>rem get yyyy

C:Documents and SettingsAdministrator>set yyyy=2013

C:Documents and SettingsAdministrator>echo 2013

2013

C:Documents and SettingsAdministrator>rem =======================

C:Documents and SettingsAdministrator>rem get mm

C:Documents and SettingsAdministrator>set mm=07

C:Documents and SettingsAdministrator>echo 07

07

C:Documents and SettingsAdministrator>rem =======================

C:Documents and SettingsAdministrator>rem get dd

C:Documents and SettingsAdministrator>set dd=22

C:Documents and SettingsAdministrator>echo 22

22

C:Documents and SettingsAdministrator>rem =======================

C:Documents and SettingsAdministrator>rem get yyyy-mm-dd

C:Documents and SettingsAdministrator>set curdate=2013 -07 -22

C:Documents and SettingsAdministrator>echo 2013 -07 -22

2013 -07 -22

C:Documents and SettingsAdministrator>

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