本文实例讲述了python实现提取百度搜索结果的方法。分享给大家供大家参考。具体实现方法如下：
# coding=utf8 import urllib2 import string import urllib import re import random #设置多个user_agents，防止百度限制IP user_agents = ['Mozilla/5.0 (Windows NT 6.1; WOW64; rv:23.0) Gecko/20130406 Firefox/23.0', 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0', 'Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US) AppleWebKit/533+ (KHTML, like Gecko) Element Browser 5.0', 'IBM WebExplorer /v0.94', 'Galaxy/1.0 [en] (Mac OS X 10.5.6; U; en)', 'Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.1; WOW64; Trident/6.0)', 'Opera/9.80 (Windows NT 6.0) Presto/2.12.388 Version/12.14', 'Mozilla/5.0 (iPad; CPU OS 6_0 like Mac OS X) AppleWebKit/536.26 (KHTML, like Gecko) Version/6.0 Mobile/10A5355d Safari/8536.25', 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/28.0.1468.0 Safari/537.36', 'Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0; TheWorld)'] def baidu_search(keyword,pn): p= {'wd': keyword} res=urllib2.urlopen(("http://www.baidu.com/s"+urllib.urlencode(p)+"&pn={0}&cl=3&rn=100").format(pn)) html=res.read() return html def getList(regex,text): arr = [] res = re.findall(regex, text) if res: for r in res: arr.append(r) return arr def getMatch(regex,text): res = re.findall(regex, text) if res: return res[0] return "" def clearTag(text): p = re.compile(u'<[^>]+>') retval = p.sub("",text) return retval def geturl(keyword): for page in range(10): pn=page*100+1 html = baidu_search(keyword,pn) content = unicode(html, 'utf-8','ignore') arrList = getList(u"<table.*".*?>.*", content) for item in arrList: regex = u"<h3.*".*?><a.*"(.*".*?>(.*" link = getMatch(regex,item) url = link[0] #获取标题 #title = clearTag(link[1]).encode('utf8') try: domain=urllib2.Request(url) r=random.randint(0,11) domain.add_header('User-agent', user_agents[r]) domain.add_header('connection','keep-alive') response=urllib2.urlopen(domain) uri=response.geturl() print uri except: continue if __name__=='__main__': geturl('python')
希望本文所述对大家的Python程序设计有所帮助。
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