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python实现猜数字游戏(无重复数字)示例分享
摘要:复制代码代码如下:importtime,randomclassGuessNum:def__init__(self):self._num=''...

复制代码 代码如下:

import time, random

class GuessNum:

def __init__(self):

self._num = ''

self.input_num = []

self.count = 1 #猜对所用次数

self.sec = 0 #猜对所用时间

self._generate_num()

def _generate_num(self): #产生不重复的四个数字

seq_zton = list(range(10))

for i in range(0, 4):

a = str(random.choice(seq_zton)) #选出一个数字

self._num += a

seq_zton.remove(int(a)) #注意a的类型

self.sec = time.clock() #开始计时

def check_answer(self):

return self._num

def check_input(self):

num_pos, num_value = 0, 0 #位置对和数值对的分别的个数

tmp = input("Please input the number you guess(No repetition),or 'c' to check the answer:")

if tmp == 'c':

print(self.check_answer())

tof = self.check_input()

return tof

elif not tmp.isalnum or not len(tmp) == 4:

print("Wrong format!")

tof = self.check_input() #需要优化

return tof

self.input_num = list(tmp)

lst_temp = list(self._num)

if self.input_num == lst_temp: #猜对

self.prt_vic()

return True

for i in lst_temp:

if i in self.input_num:

if lst_temp.index(i) == self.input_num.index(i): #位置也相同

num_pos += 1

num_value += 1

else:

num_value += 1

self.prt_state(num_pos, num_value)

self.count += 1

return False

def prt_state(self, num_pos, num_value):

print("You've got %d numbers with the right position and %d numbers with the right value only" % (num_pos, num_value))

def prt_vic(self):

t = time.clock()

self.sec = t - self.sec

print("Congratulations!You have successfully got the right number!")

print("%d times and %.2f sec in total to get the right answer" % (self.count, self.sec))

gn = GuessNum()

while True:

ss = gn.check_input()

if ss:

b = input("Continue? y/n:")

if b == 'n':

break

else:

gn = GuessNum()

continue

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