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压缩包密码破解示例分享(类似典破解)
摘要:昨天翻硬盘,找到一个好东西,可惜自己加了密码自己不记得了。试了几个常用的没试出来,于是写了这么个小脚本来替我尝试。。呵呵,还真给解出来了。p...

昨天翻硬盘,找到一个好东西,可惜自己加了密码自己不记得了。试了几个常用的没试出来,于是写了这么个小脚本来替我尝试。。呵呵,还真给解出来了。

python脚本内容如下,跑跑自己加密的压缩包还不错

复制代码 代码如下:

# -*- coding: utf-8 -*-

import sys,os

def IsElementUniq(list):

"""

判断list中的元素是否为唯一的

"""

for word in list:

if list.count(word)>1:

return False

return True

def GenPswList():

"""

要求用户输入词,并根据单词组合密码,只尝试四个单词来组合,并限制密码长度为20。写的比较挫

"""

psw=raw_input('input a word>')

wordlist = []

while psw:

wordlist.append(psw)

psw=raw_input('input a word>')

print wordlist

global g_pswlist

g_pswlist = []

for word in wordlist:

g_pswlist.append(word)

for word1 in wordlist:

for word2 in wordlist:

locallist = [word1, word2]

if IsElementUniq(locallist):

tmp = word1 + word2

if len(tmp) < 20:

g_pswlist.append(tmp)

for word1 in wordlist:

for word2 in wordlist:

for word3 in wordlist:

locallist = [word1, word2, word3]

if IsElementUniq(locallist):

tmp = word1 + word2 + word3

if len(tmp) < 20:

g_pswlist.append(tmp)

for word1 in wordlist:

for word2 in wordlist:

for word3 in wordlist:

for word4 in wordlist:

locallist = [word1, word2, word3, word4]

if IsElementUniq(locallist):

tmp = word1 + word2 + word3 + word4

if len(tmp) < 20:

g_pswlist.append(tmp)

print 'gen psw is:', g_pswlist

def TestUnZipPack(filename):

"""

尝试用密码来解压压缩包

"""

command = ""

for psw in g_pswlist:

command = "7z e -p%s -y %s" %(psw,filename)

print command

ret = os.system(command)

if ret == 0:

print 'right psw is ', psw

break

def main(filename):

GenPswList()

TestUnZipPack(filename)

if __name__ == '__main__':

if len(sys.argv) != 2:

print 'argv error'

print 'example:test_7z_psw.py 1.7z'

sys.exit(1)

main(sys.argv[1])

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